2*X^2-4X-3*根号（X^2-2X-4)=10

2*X^2-4X-3*根号（X^2-2X-4)=10
方程变形为:
2(X^2-2X-4)-3√(X^2-2X-4)-2=0,
令,√(X^2-2X-4)=t,(t≥0),则有
2t^2-3t-2=0,
(2t+1)(t-2)=0,
t1=-1/2(不合.舍去,因为t≥0),
t2=2.

则有,,√(X^2-2X-4)=t=2,
X^2-2X-8=0,
(X-4)(X+2)=0,
X1=4,X2=-2,
经检验,X1=4,X2=-2,是方程的解.